Tunnel Rush

    Rewrite the equation so that all (y)-terms are on one side and all (x)-terms are on the other:

    Right side:

    [ y = \frac{1}{-2x^3 - C} ]

    [ y = \frac{1}{C - 2x^3} ]

    Left side:

    [ \frac{1}{y^2} , dy = 6x^2 , dx ]

    [ \int y^{-2} , dy = \int 6x^2 , dx ]

    [ \frac{1}{y} = -2x^3 - C ]

    Solve The Differential Equation. Dy Dx = 6x2y2 [patched] May 2026

    Rewrite the equation so that all (y)-terms are on one side and all (x)-terms are on the other:

    Right side:

    [ y = \frac{1}{-2x^3 - C} ]

    [ y = \frac{1}{C - 2x^3} ]

    Left side:

    [ \frac{1}{y^2} , dy = 6x^2 , dx ]

    [ \int y^{-2} , dy = \int 6x^2 , dx ]

    [ \frac{1}{y} = -2x^3 - C ]